10 examples of 'index out of range' in Go

189
func isInBounds(data []byte, i int) bool {
190
	return i >= 0 && i < len(data)
191
}

161
func (heap *Heap) withinRange(index int) bool {
162
	return index >= 0 && index < heap.list.Size()
163
}

98
func checkIndex(min, max, i int) error {
99
	if i < min {
100
		return NewErrBadIndex("%v, min=%v", i, min)
101
	}
102
	if i > max { // allow max
103
		return NewErrBadIndex("%v, max=%v", i, max)
104
	}
105
	return nil
106
}

293
func (sc *SliceColumn) inBounds(i int) error {
294
	if i >= 0 && i < sc.Len() {
295
		return nil
296
	}
297
298
	return fmt.Errorf("index %d out of bounds [0:%d]", i, sc.Len())
299
}

253
func (Bool) IndexSet(index, value Object) error {
254
	return ErrNotIndexAssignable
255
}

269
func (matrix *DenseFloat64Matrix) IntAt(i, j int) int {
270
  return int(matrix.values[matrix.index(i, j)])
271
}

77
func (pstruct *Struct) SetIndex(index, value interface{}) int {
78
	sindex := int(index.(int64))
79
	if sindex < 0 || sindex >= len(pstruct.Values) {
80
		return core.ErrIndexOut
81
	}
82
	pstruct.Values[sindex] = value
83
	return 0
84
}

88
func (i *Int) InRange(lowerLimit int, upperLimit int) structure.Int {
89
	if i.value != nil {
90
		if *i.value < lowerLimit || *i.value > upperLimit {
91
			i.base.ReportError(ErrorValueNotInRange(*i.value, lowerLimit, upperLimit))
92
		}
93
	}
94
	return i
95
}

213
func (me *Int3x3) AccessIndex(i, j int) interface{} {
214
	if j >= 0 {
215
		i = index2D(i, j, len(me))
216
	}
217
	return &me[i]
218
}

157
func (s *Base) InRange(index int) bool {
158
	return index >= 0 && index < s.Len()
159
}