10 examples of 'fibonacci series in javascript using array' in JavaScript

4
export default function* fibonacci() {
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    let f = (a, b) => a + b;
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    let s = series(f, 1, 1);
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    let predicate = n => n < Number.MAX_SAFE_INTEGER;
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    yield* takeWhile(s, predicate);
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}

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function getFibonacci(n) {
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  var fibarr = [];
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  var i = 0;
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  while(i<n) {
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    if(i<=1) {
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      fibarr.push(i);
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    }else{
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      fibarr.push(fibarr[i-1] + fibarr[i-2])
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    }
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    i++;
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  }
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  return fibarr;
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}

2
function fibonacci(n) {
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    return fibonacciRecursion(n, [1,1]);
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}

1
function fibonacci(n, a = 0, b = 1) {
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  return n < 1 ? a : fibonacci(n - 1, a + b, a);
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}

1
function fibonacci(num) {
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    var n = Number(num);
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    var first = 0;
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    var second = 1;
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    var result = 0;
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    for (var i = 1; i <= n; i++) {
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    	result = first + second;
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    	first = second;
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    	second = result;
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        console.log(i + ": " + first + "\n");
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    }
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}

115
function fibonacci( n ) {
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	if ( n < 2 ) {
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		return n;
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	}
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	return fibonacci( n-1 ) + fibonacci( n-2 );
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}

1
function fibonacci(n) {
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  const sequence = [0, 1];
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  for (let i = 2; i <= n; i++) {
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    sequence[i] = sequence[i - 1] + sequence[i - 2];
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  }
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  return sequence[n];
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}

5
function fibonacci(x) {
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  return x <= 1 ? x : fibonacci(x - 1) + fibonacci(x - 2);
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}

1
function fibonacci(n) {
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  let a = 1
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  let b = 0
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  while (n > 0) {
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    let temp = a
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    a = a + b
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    b = temp
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    n--
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  }
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  return b
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}

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function fibonacci(n) {
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	var res;
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	if (fibonacci.stack[n]) return fibonacci.stack[n];
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	if (n < 2)
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		res = 1;
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	else
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		res = fibonacci(n - 2) + fibonacci(n - 1);
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	return (fibonacci.stack[n] = res);
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}