10 examples of 'matlab angle between two points' in JavaScript

54
export function calculateAngleBetweenPoints(A: GeometricalPoint, B: GeometricalPoint, C: GeometricalPoint): number {
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  // Calculate length of each line in the triangle formed by A, B, C.
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  const AB = calculateDistanceBetweenTwoPoints(A, B);
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  const BC = calculateDistanceBetweenTwoPoints(B, C);
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  const AC = calculateDistanceBetweenTwoPoints(A, C);
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  // Arccosine is the inverse function of a cosine, i.e. given a cosine,
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  // it calculates the corresponding angle.
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  return Math.acos((BC * BC + AB * AB - AC * AC) / (2 * BC * AB));
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};

241
function angleBetween(v1, v2) {
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	var adotb = (v1[0]*v2[0] + v1[1]*v2[1])/Math.sqrt((v1[0]*v1[0] + v1[1]*v1[1])*(v2[0]*v2[0] + v2[1]*v2[1]));
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	var cross = v1[0]*v2[1]-v1[1]*v2[0];
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	return (cross!=0?cross/Math.abs(cross):1)*Math.acos(adotb);
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}

46
export function angleBetween(u: number[], v: number[]): number {
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    var ux = u[0],
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        uy = u[1],
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        vx = v[0],
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        vy = v[1];
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    var num = ux * vx + uy * vy;
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    var den = Math.sqrt(ux * ux + uy * uy) * Math.sqrt(vx * vx + vy * vy);
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    return Math.acos(num / den);
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}

329
function getAngle(a, b) {
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    const point = { x: b.x - a.x, y: b.y - a.y };
331
    return Math.atan2(point.y, point.x);
332
}

369
function angleBetween(v0, v1) {
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	var p = v0.x*v1.x + v0.y*v1.y;
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	var n = Math.sqrt((Math.pow(v0.x, 2)+Math.pow(v0.y, 2)) * (Math.pow(v1.x, 2)+Math.pow(v1.y, 2)));
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	var sign = v0.x*v1.y - v0.y*v1.x < 0 ? -1 : 1;
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	var angle = sign*Math.acos(p/n);
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	//var angle = Math.atan2(v0.y, v0.x) - Math.atan2(v1.y,  v1.x);
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	return angle;
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}

260
function angle(a, b) {
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  return Math.atan2(b[1] - a[1], b[0] - a[0]);
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}

45
function getAngle(x1, y1, x2, y2) {
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	return Math.atan2(y2-y1, x2-x1);
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}

105
angleWithSep(x, y) {
106
    return Math.atan2(
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        this.x * y - this.y * x,
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        this.x * x + this.y * y);
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}

105
function findAngle(A, B, C) {
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  //A first point; C second point; B center point
107
  var pi = 3.14159265;
108
  var AB = Math.sqrt(Math.pow(B[0] - A[0], 2) + Math.pow(B[1] - A[1], 2));
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  var BC = Math.sqrt(Math.pow(B[0] - C[0], 2) + Math.pow(B[1] - C[1], 2));
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  var AC = Math.sqrt(Math.pow(C[0] - A[0], 2) + Math.pow(C[1] - A[1], 2));
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  return Math.acos((BC * BC + AB * AB - AC * AC) / (2 * BC * AB)) * (180 / pi);
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}

180
solveAngle(a, b = this) {
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    return Math.atan2(a.y - b.y, a.x - b.x);
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}