10 examples of 'add days to date python' in Python

668
def add_years(d, years):
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    """
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    Add 'year' years to the date 'd'.
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    Return a date that's `years` years after the date (or datetime)
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    object `d`. Return the same calendar date (month and day) in the
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    destination year, if it exists, otherwise use the following day
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    (thus changing February 29 to March 1).
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    source: https://stackoverflow.com/a/15743908/1518684
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    Parameters:
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    ----------
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    d: datetime.date
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        The date to which 'years' years should be added.
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    years: int
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        The number of years to add to date.
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    Returns:
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    ----------
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    new_d: datetime.date
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        Date d incremented by 'years' years.
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    """
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    try:
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        return d.replace(year = d.year + years)
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    except ValueError:
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        return d + (date(d.year + years, 1, 1) - date(d.year, 1, 1))

40
def add_days(self, days):
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    self._days += days

69
def add_month_based_on_weekday(date):
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    # Is the weekday of this date the last one?
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    is_last_weekday = (date + datetime.timedelta(weeks=1)).month != date.month
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    # Some magic which pushes and pulls some weeks until
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    # it fits right.
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    new_date = date + datetime.timedelta(weeks=4)
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    if (new_date.day + 6) // 7 < (date.day + 6) // 7:
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        new_date += datetime.timedelta(weeks=1)
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    next_month = add_month(date, override_day=1)
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    if new_date.month == (next_month.month - 1 if next_month.month > 1 else 12):
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        new_date += datetime.timedelta(weeks=1)
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    elif new_date.month == (next_month.month + 1 if next_month.month < 12 else 1):
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        new_date += datetime.timedelta(weeks=-1)
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    # If the weekdate of the original date was the last one,
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    # and there is some room left, add a week extra so this
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    # will result in a last weekday of the month again.
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    if is_last_weekday and (new_date + datetime.timedelta(weeks=1)).month == new_date.month:
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        new_date += datetime.timedelta(weeks=1)
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    return new_date

9
def days_since_1900(date):
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    """Convert string date to days since 1/1/1900
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    Intakes a date month/day/year and returns number of days since 1/1/1900
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    convert_date('1/1/1950') -> 18262. Note 1900 was not leap year
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    """
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    days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]  
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    date_array = date.split('-')
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    month = int(date_array[1])
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    day = int(date_array[2])
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    year = int(date_array[0]) - 1900 #looking for number of days since 1900
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# Start with days in previous years
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    days_prev_years = year * 365
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# Add the appropriate leap years
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    leap_years = int(year/4)
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    if (year%4 == 0 and month < 3):
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        leap_years = leap_years - 1
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    days_prev_years += leap_years
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# Now count up the days this year, start with days in previous months
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    days_this_year = 0
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    for imonth in range(0,month-1):
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        days_this_year += days_in_month[imonth]
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# Add previous days this month
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    days_this_year += day-1
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    days = days_prev_years + days_this_year
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    return(days)

517
def daysbetween(day1, month1, year1, day2, month2, year2):
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    """Given two dates it returns the number of days between them.
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    If date1 is earlier than date2 then the result will be positive."""
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    return daycount(year2, month2, day2) - daycount(year1, month1, day1)

30
def get_todays_date():
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    return timezone.now().astimezone(PACIFIC_TIME).date()

12
def add_days_delta(date_from, days_delta):
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    if not date_from:
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        return date_from
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    next_date = fields.Date.from_string(date_from) + timedelta(days=days_delta)
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    return fields.Date.to_string(next_date)

73
def python_to_ABAP_date(py_date):
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    return "{:04d}{:02d}{:02d}".format(py_date.year, py_date.month, py_date.day)

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def add_day(x):
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    if x not in self.weekdays:
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        self.weekdays.append(x)

71
def toDate(mon, yr):
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    #Parse month
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    newMon = monthMapper(mon)
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    #Parse day
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    newDay = 1
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    #Parse year
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    if yr < 50:
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        yr += 2000
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    elif yr <= 99:
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        yr += 1900
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    newYr = yr
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    return date(newYr, int(newMon), newDay)