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99 def common(lst): 100 return set.intersection(*map(set, [i for i in lst]))
59 def list_find(l, element): 60 for i, e in enumerate(l): 61 if e == element: 62 return i 63 return None
24 def commonChars(self, A): 25 return list(reduce(Counter.__and__, map(Counter, A)).elements())
30 def intersect(first_list, second_list): 31 32 return [x for x in first_list if x in second_list]