# 10 examples of 'find duplicate in array interviewbit solution' in Python

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 2 def findDuplicate(self, nums: List[int]) -> int: 3 p1, p2 = nums[0], nums[nums[0]] 4 while nums[p1] != nums[p2]: 5 p1 = nums[p1] 6 p2 = nums[nums[p2]] 7 p2 = 0 8 while nums[p1] != nums[p2]: 9 p1 = nums[p1] 10 p2 = nums[p2] 11 return nums[p1]
 29 def main(): 30 sol = Solution() 31 assert sol.containsNearbyDuplicate([-1, -1], 1)
 2 def containsDuplicate(self, nums): 3 """ 4 :type nums: List[int] 5 :rtype: bool 6 """ 7 nums_sort = sorted(nums) 8 for i, _ in enumerate(nums_sort[:-1]): 9 if nums_sort[i] == nums_sort[i + 1]: 10 return True 11 12 return False
 4 def repeatedNumber(self, A): 5 ''' 6 # This is the marker concept, by list modification 7 A = list(A) 8 if len(A) <= 1: 9 return -1 10 for i in range(len(A)): 11 num = abs(A[i]) 12 if A[num]>=0: 13 A[num] = -1 * A[num] # marking negative means already visited A[i] 14 else: 15 return num 16 return -1 17 ''' 18 19 # This is modified Floyd Warshall concept, cycle in linked list type 20 # https://medium.com/solvingalgo/solving-algorithmic-problems-find-a-duplicate-in-an-array-3d9edad5ad41 21 22 slow, fast = A[0], A[A[0]] 23 while slow!=fast: 24 slow = A[slow] 25 fast = A[A[fast]] 26 # the slow and fast pointers are at the same point now, i.e start point of cycle 27 slow = 0 28 while slow!=fast: 29 slow = A[slow] 30 fast = A[fast] 31 if slow == 0: 32 return -1 33 else: 34 return slow
 10 def removeDuplicates(self, nums): 11 """ 12 :type nums: List[int] 13 :rtype: int 14 """ 15 if len(nums) == 0: 16 return 0 17 flag, count = 0, 0 18 for i in xrange(1,len(nums)): 19 if nums[count] == nums[i] and flag == 0: 20 count += 1 21 nums[count], nums[i] = nums[i], nums[count] 22 flag = 1 23 elif nums[count] != nums[i]: 24 count += 1 25 nums[count], nums[i] = nums[i], nums[count] 26 flag = 0 27 return count+1
 51 def subsetsWithDup(self, nums): 52 """ 53 :type nums: List[int] 54 :rtype: List[List[int]] 55 """ 56 result = [] 57 self.subsetsWithDupRecu(result, [], sorted(nums)) 58 return result
 6 def removeDuplicates(self, nums: List[int]) -> int: 7 if len(nums) == 0: return 0 8 j = 1 9 for i in range(1, len(nums)): 10 if nums[i] != nums[i-1]: 11 nums[j] = nums[i] 12 j += 1 13 return j
 2 def removeDuplicates(self, nums: List[int]) -> int: 3 if not nums : 4 return 0 5 j = 1 6 for i in range( 1 , len(nums)): 7 if nums[i] != nums[i - 1] : 8 nums[j] = nums[i] 9 j += 1 10 return j
 47 def removeDuplicates_another_loop_style(self, A): 48 """ 49 Yet another looping style - double while loops 50 :param A: list 51 :return: "shrunk" list 52 """ 53 length = len(A) 54 55 if length==0 or length==1: 56 return length 57 58 closed_ptr = 0 59 open_ptr = 1 60 while open_ptr
 5 def checkPossibility(self, nums): 6 """ 7 :type nums: List[int] 8 :rtype: bool 9 """ 10 modified, prev = False, nums[0] 11 for i in xrange(1, len(nums)): 12 if prev > nums[i]: 13 if modified: 14 return False 15 if i-2 < 0 or nums[i-2] <= nums[i]: 16 prev = nums[i] # nums[i-1] = nums[i], prev = nums[i] 17 # else: 18 # prev = nums[i-1] # nums[i] = nums[i-1], prev = nums[i] 19 modified = True 20 else: 21 prev = nums[i] 22 return True