# 10 examples of 'find duplicate in array interviewbit solution' in Python

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``2def findDuplicate(self, nums: List[int]) -&gt; int:3    p1, p2 = nums[0], nums[nums[0]]4    while nums[p1] != nums[p2]:5        p1 = nums[p1]6        p2 = nums[nums[p2]]7    p2 = 08    while nums[p1] != nums[p2]:9        p1 = nums[p1]10        p2 = nums[p2]11    return nums[p1]``
``29def main():30    sol = Solution()31    assert sol.containsNearbyDuplicate([-1, -1], 1)``
``2def containsDuplicate(self, nums):3    """4    :type nums: List[int]5    :rtype: bool6    """7    nums_sort = sorted(nums)8    for i, _ in enumerate(nums_sort[:-1]):9        if nums_sort[i] == nums_sort[i + 1]:10            return True11    12    return False``
``4def repeatedNumber(self, A):5    '''6    # This is the marker concept, by list modification7    A = list(A)8    if len(A) &lt;= 1:9        return -110    for i in range(len(A)):11        num = abs(A[i])12        if A[num]&gt;=0:13            A[num] = -1 * A[num] # marking negative means already visited A[i]14        else:15            return num16    return -117    '''18    19    # This is modified Floyd Warshall concept, cycle in linked list type20    # https://medium.com/solvingalgo/solving-algorithmic-problems-find-a-duplicate-in-an-array-3d9edad5ad4121    22    slow, fast = A[0], A[A[0]]23    while slow!=fast:24        slow = A[slow]25        fast = A[A[fast]]26    # the slow and fast pointers are at the same point now, i.e start point of cycle27    slow = 028    while slow!=fast:29        slow = A[slow]30        fast = A[fast]31    if slow == 0:32        return -133    else:34        return slow``
``10def removeDuplicates(self, nums):11    """12    :type nums: List[int]13    :rtype: int14    """15    if len(nums) == 0:16        return 017    flag, count  = 0, 018    for i in xrange(1,len(nums)):19        if nums[count] == nums[i] and flag == 0:20            count += 121            nums[count], nums[i] = nums[i], nums[count]22            flag = 123        elif nums[count] != nums[i]:24            count += 125            nums[count], nums[i] = nums[i], nums[count]26            flag = 027    return count+1``
``51def subsetsWithDup(self, nums):52    """53    :type nums: List[int]54    :rtype: List[List[int]]55    """56    result = []57    self.subsetsWithDupRecu(result, [], sorted(nums))58    return result``
``6def removeDuplicates(self, nums: List[int]) -&gt; int:7    if len(nums) == 0: return 08    j = 19    for i in range(1, len(nums)):10        if nums[i] != nums[i-1]:11            nums[j] = nums[i]12            j += 113    return j``
``2def removeDuplicates(self, nums: List[int]) -&gt; int:3    if not nums :4        return 05    j = 16    for i in range( 1 , len(nums)):7        if nums[i] != nums[i - 1] :8            nums[j] = nums[i]9            j += 110    return j``
``47def removeDuplicates_another_loop_style(self, A):48    """49    Yet another looping style - double while loops50    :param A: list51    :return: "shrunk" list52    """53    length = len(A)5455    if length==0 or length==1:56        return length5758    closed_ptr = 059    open_ptr = 160    while open_ptr``
``5def checkPossibility(self, nums):6        """7        :type nums: List[int]8        :rtype: bool9        """10        modified, prev = False, nums[0]11        for i in xrange(1, len(nums)):12            if prev &gt; nums[i]:13                if modified:14                    return False15                if i-2 &lt; 0 or nums[i-2] &lt;= nums[i]:16                    prev = nums[i]    # nums[i-1] = nums[i], prev = nums[i]17#               else:18#                   prev = nums[i-1]  # nums[i] = nums[i-1], prev = nums[i]19                modified = True20            else:21                prev = nums[i]22        return True``