3 examples of 'find the maximum element in a matrix using functions python' in Python

Every line of 'find the maximum element in a matrix using functions python' code snippets is scanned for vulnerabilities by our powerful machine learning engine that combs millions of open source libraries, ensuring your Python code is secure.

All examples are scanned by Snyk Code

By copying the Snyk Code Snippets you agree to
this disclaimer
73def findMax(rows):
74 for row in range(len(rows)-1, 0, -1):
75 # print("row=",row)
76 for col in range(0,row):
77 # print(rows[row][col],rows[row][col+1])
78 rows[row-1][col] += max(rows[row][col],rows[row][col+1])
79 print(rows[row-1][col])
80 print("\n")
81 return rows
Important

Use secure code every time

Secure your code as it's written. Use Snyk Code to scan source code in minutes – no build needed – and fix issues immediately. Enable Snyk Code

11def leftmost_min_element_divide_and_conquer(
12 matrix, leftmost_min_element_in_each_row, row_start, row_end, step):
13 if row_start == row_end:
14 leftmost_min_element_in_each_row[row_start] = \
15 find_leftmost_min_element_in_row(
16 matrix, row_start, 0, len(matrix[row_start]) - 1)
17 else:
18 # Construct a submatrix consisting of the even-numbered rows
19 sub_matrix_row_start = row_start + step
20 sub_matrix_row_end = 0
21
22 if row_end % 2 == 0 or ((row_end - row_start) // step) % 2 == 0:
23 sub_matrix_row_end = row_end - step
24 elif ((row_end - row_start) // step) % 2 == 1:
25 sub_matrix_row_end = row_end
26
27 leftmost_min_element_divide_and_conquer(
28 matrix, leftmost_min_element_in_each_row,
29 sub_matrix_row_start, sub_matrix_row_end, step * 2)
30
31 leftmost_min_element_in_odd_numbered_rows(
32 matrix, leftmost_min_element_in_each_row, row_start, row_end, step)
199def matrix_elem(matrix, i, j, val=None):
200 """
201 Reads/writes the elements of an affine transform.
202
203 1. 3x3 rotational component;
204 matrix_elem(m, i, j) for i=0..3, j=0..3
205 2. 3x1 translational component:
206 matrix_elem(m, 3, i) for i=0..3)
207 """
208 k = i*3 + j
209 if val is None:
210 return matrix[k]
211 else:
212 matrix[k] = val
213 return val

Related snippets