10 examples of 'get day from date python' in Python

721
def first_day_of_month(date):
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    ddays = int(date.strftime("%d")) - 1
723
    delta = timedelta(days=ddays)
724
    return date - delta

105
def get_end_day(date):
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    """
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    """
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    year, month, day = date.split("-")
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    end = datetime.datetime(int(year), int(month), int(day))    
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    end = end + datetime.timedelta(1) - datetime.timedelta(microseconds=1)
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    return end

6
def dayOfMonth(M):
7
    return (28 if (M == 2) else 31-(M-1)%7%2)

13
@staticmethod
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def day(date_string):
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    today = datetime.date.today()
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    date_string = date_string.strip().lower()
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    if date_string in OPT_TODAY:
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        return datetime.date(today.year, today.month, today.day)
19
    elif date_string in OPT_YESTERDAY:
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        return datetime.date(today.year, today.month, today.day) - datetime.timedelta(days=1)
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    elif re.search(r'(\d{1,3}|a) days? ago', date_string):
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        return Parse.n_day(date_string)
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    else:
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        return Parse.date(date_string)

517
def daysbetween(day1, month1, year1, day2, month2, year2):
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    """Given two dates it returns the number of days between them.
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    If date1 is earlier than date2 then the result will be positive."""
520
    return daycount(year2, month2, day2) - daycount(year1, month1, day1)

9
def days_since_1900(date):
10
    """Convert string date to days since 1/1/1900
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    Intakes a date month/day/year and returns number of days since 1/1/1900
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    convert_date('1/1/1950') -> 18262. Note 1900 was not leap year
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    """
14
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    days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]  
16
    date_array = date.split('-')
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    month = int(date_array[1])
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    day = int(date_array[2])
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    year = int(date_array[0]) - 1900 #looking for number of days since 1900
20
21
# Start with days in previous years
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    days_prev_years = year * 365
23
24
# Add the appropriate leap years
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    leap_years = int(year/4)
26
    if (year%4 == 0 and month < 3):
27
        leap_years = leap_years - 1
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    days_prev_years += leap_years
29
30
# Now count up the days this year, start with days in previous months
31
    days_this_year = 0
32
    for imonth in range(0,month-1):
33
        days_this_year += days_in_month[imonth]
34
   
35
# Add previous days this month
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    days_this_year += day-1
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    days = days_prev_years + days_this_year
39
    return(days)

22
def _dayofmonth(hardday, month, year):
23
    '''
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    Returns a valid day of the month given the desired value.
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    Negative values are interpreted as offset backwards from the last day of the month, with -1 representing the
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    last day of the month.  Out-of-range values are clamped to the first or last day of the month.
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    '''
29
    newday = hardday
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    daysinmonth = calendar.monthrange(year, month)[1]
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    if newday < 0:
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        newday = daysinmonth + hardday + 1
33
    newday = max(1, min(newday, daysinmonth))
34
    return newday

66
def get_day(form="%y%m%d"):
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	day = time.strftime(str(form))
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	return day

403
def internal_get_day(dt: Value):
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    return internal_process_unary_fcn_val(lambda x: date.fromisoformat(x).day, dt)

107
def getDaysInMonth(self, mth, year):
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    days = 0
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    if mth in [1, 3, 5, 7, 8, 10, 12]:
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        days = 31
111
    elif mth in [4, 6, 9, 11]:
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        days = 30
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    elif (mth == 2 and self.isLeapYear(year)):
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        days = 29
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    else:
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        days = 28
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    return days