10 examples of 'get day from date python' in Python

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721def first_day_of_month(date):
722 ddays = int(date.strftime("%d")) - 1
723 delta = timedelta(days=ddays)
724 return date - delta
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105def get_end_day(date):
106 """
107 """
108 year, month, day = date.split("-")
109 end = datetime.datetime(int(year), int(month), int(day))
110 end = end + datetime.timedelta(1) - datetime.timedelta(microseconds=1)
111
112 return end
6def dayOfMonth(M):
7 return (28 if (M == 2) else 31-(M-1)%7%2)
13@staticmethod
14def day(date_string):
15 today = datetime.date.today()
16 date_string = date_string.strip().lower()
17 if date_string in OPT_TODAY:
18 return datetime.date(today.year, today.month, today.day)
19 elif date_string in OPT_YESTERDAY:
20 return datetime.date(today.year, today.month, today.day) - datetime.timedelta(days=1)
21 elif re.search(r'(\d{1,3}|a) days? ago', date_string):
22 return Parse.n_day(date_string)
23 else:
24 return Parse.date(date_string)
517def daysbetween(day1, month1, year1, day2, month2, year2):
518 """Given two dates it returns the number of days between them.
519 If date1 is earlier than date2 then the result will be positive."""
520 return daycount(year2, month2, day2) - daycount(year1, month1, day1)
9def days_since_1900(date):
10 """Convert string date to days since 1/1/1900
11 Intakes a date month/day/year and returns number of days since 1/1/1900
12 convert_date('1/1/1950') -> 18262. Note 1900 was not leap year
13 """
14
15 days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
16 date_array = date.split('-')
17 month = int(date_array[1])
18 day = int(date_array[2])
19 year = int(date_array[0]) - 1900 #looking for number of days since 1900
20
21# Start with days in previous years
22 days_prev_years = year * 365
23
24# Add the appropriate leap years
25 leap_years = int(year/4)
26 if (year%4 == 0 and month < 3):
27 leap_years = leap_years - 1
28 days_prev_years += leap_years
29
30# Now count up the days this year, start with days in previous months
31 days_this_year = 0
32 for imonth in range(0,month-1):
33 days_this_year += days_in_month[imonth]
34
35# Add previous days this month
36 days_this_year += day-1
37
38 days = days_prev_years + days_this_year
39 return(days)
22def _dayofmonth(hardday, month, year):
23 '''
24 Returns a valid day of the month given the desired value.
25
26 Negative values are interpreted as offset backwards from the last day of the month, with -1 representing the
27 last day of the month. Out-of-range values are clamped to the first or last day of the month.
28 '''
29 newday = hardday
30 daysinmonth = calendar.monthrange(year, month)[1]
31 if newday < 0:
32 newday = daysinmonth + hardday + 1
33 newday = max(1, min(newday, daysinmonth))
34 return newday
66def get_day(form="%y%m%d"):
67 day = time.strftime(str(form))
68 return day
403def internal_get_day(dt: Value):
404 return internal_process_unary_fcn_val(lambda x: date.fromisoformat(x).day, dt)
107def getDaysInMonth(self, mth, year):
108 days = 0
109 if mth in [1, 3, 5, 7, 8, 10, 12]:
110 days = 31
111 elif mth in [4, 6, 9, 11]:
112 days = 30
113 elif (mth == 2 and self.isLeapYear(year)):
114 days = 29
115 else:
116 days = 28
117 return days

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