# 10 examples of 'longest increasing subsequence python' in Python

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``50def longest_increasing_subsequence(a, verbose=False):5152    s = a[:]53    s.sort()5455    (cost, alignment) = lcs(a, s)5657    if verbose:58        print59        print "input:  ", a60        print "sorted: ", s6162        print 'cost:', cost63        print64        for (a,b) in alignment:65            print '  %16s => %s' % (a,b)66        print6768    return [a for (a,b) in alignment if a is not None and b is not None]``
``10def longestCommonSubsequence(self, A, B):11    """12    let f(i, j) represents the LCS END WITH A[i], B[j]13    f(i, j) = f(i-1, j-1)+1, if A[i] == A[j]14    f(i, j) = max{f(i-1, j), f(i, j-1)}, otherwise1516    :param A: str17    :param B: str18    :return: The length of longest common subsequence of A and B.19    """20    m = len(A)21    n = len(B)22    f = [[0 for _ in xrange(n+1)] for _ in xrange(m+1)]2324    if m == 0 or n == 0:25        return 02627    for i in xrange(1, m+1):28        for j in xrange(1, n+1):29            if A[i-1] == B[j-1]:30                f[i][j] = f[i-1][j-1]+131            else:32                f[i][j] = max(f[i][j-1], f[i-1][j])3334    return f[-1][-1]``
``2def longestPalindromeSubseq(self, s: str) -> int:3    n = len(s)4    dp = [[0 for _ in range(n)] for _ in range(n)]5    for i in range(n - 1, -1, -1):6        dp[i][i] = 17        for j in range(i + 1, n):8            if s[i] == s[j]:9                dp[i][j] = dp[i + 1][j - 1] + 210            else:11                dp[i][j] = max(dp[i + 1][j], dp[i][j - 1])12    return dp[0][n - 1]``
``6def longestConsecutive(self, nums):7    """8    :type nums: List[int]9    :rtype: int10    """11    visited = set()12    for num in nums:13        visited.add(num)1415    max_len = 016    for num in nums:17        if num - 1 not in visited:18            curr = 019            item = num20            while item in visited:21                curr += 122                item += 123            max_len = max(max_len, curr)24    return max_len``
``37def longestCommonPrefix(self, array):38    if array is None or len(array) == 0:39        return ''4041    if len(array) == 1:42        return array[0]4344    half = len(array) / 245    longest_left = self.longestCommonPrefix(array[:half])46    longest_right = self.longestCommonPrefix(array[half:])4748    min_length = min(len(longest_left), len(longest_right))49    for index in xrange(min_length):50        if longest_left[index] != longest_right[index]:51            return longest_left[:index]5253    return longest_left[:min_length]``
``47def longestConsecutive(self, nums):48    """49    :type nums: list[int]50    :rtype: int51    """52    ans = 05354    if not nums:55        return ans5657    nums.sort()5859    size = 16061    for i in range(1, len(nums)):62        if nums[i] == nums[i - 1]:63            continue6465        if nums[i] == nums[i - 1] + 1:66            size += 167        else:68            size = 16970        if size > ans:71            ans = size7273    return ans if ans > 0 else size``
``2def longestCommonPrefix(self, strs):3  """4  :type strs: List[str]5  :rtype: str6  """7  if len(strs) == 0:8    return ""9  i = 010  j = 011  end = 012  while j < len(strs) and i < len(strs[j]):13    if j == 0:14      char = strs[j][i]15    else:16      if strs[j][i] != char:17        break1819    if j == len(strs) - 1:20      i += 121      j = 022      end += 123    else:24      j += 12526  return strs[j][:end]``
``8def longestCommonPrefix(self, strs):9    if not strs: return ""10    l = min(map(len, strs))11    i = 012    while i < l:13        char = strs[0][i]14        for s in strs:15            if s[i] != char:16                return strs[0][:i]1718        i += 11920    return strs[0][:i]``
``2def lengthOfLongestSubstring(self, s):3    result = 04    left = 05    last = {}6    for i in range(len(s)):7        if s[i] in last and left <= last[s[i]]:8            left = last[s[i]] + 19        last[s[i]] = i 10        result = max(result, i - left + 1)11    return result``
``57def lengthOfLongestSubstring(self, s):58    # https://leetcode.com/articles/longest-substring-without-repeating-characters/59    charMap = {}60    for i in range(256):61        charMap[i] = -162    ls = len(s)63    i = max_len = 064    for j in range(ls):65        # Note that when charMap[ord(s[j])] >= i, it means that there are66        # duplicate character in current i,j. So we need to update i.67        if charMap[ord(s[j])] >= i:68            i = charMap[ord(s[j])] + 169        charMap[ord(s[j])] = j70        max_len = max(max_len, j - i + 1)71    return max_len``