How to use 'maximum sum subarray of size k' - Python

How to use 'maximum sum subarray of size k' in Python

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huiwenhw/interview-prep

13 def max_subarray(nums):
14     """
15     :type nums: List[int]
16     :rtype: int
17     """
18     currsum, maxn = 0, float('-inf')
19     for i in range(len(nums)):
20         if currsum + nums[i] > 0:
21             currsum += nums[i]
22             maxn = max(maxn, currsum)
23         else:				# to get max of -ve integers
24             currsum = 0
25             maxn = max(maxn, nums[i])
26     return maxn

gavinfish/leetcode-share

9 def maxSubArray(self, nums):
10     """
11     :type nums: List[int]
12     :rtype: int
13     """
14     if not nums:
15         return 0
16     length = len(nums)
17     current = nums[0]
18     m = current
19     for i in range(1, length):
20         if current < 0:
21             current = 0
22         current += nums[i]
23         m = max(current, m)
24     return m

13	def max_subarray(nums):
14	"""
15	:type nums: List[int]
16	:rtype: int
17	"""
18	currsum, maxn = 0, float('-inf')
19	for i in range(len(nums)):
20	if currsum + nums[i] > 0:
21	currsum += nums[i]
22	maxn = max(maxn, currsum)
23	else: # to get max of -ve integers
24	currsum = 0
25	maxn = max(maxn, nums[i])
26	return maxn

9	def maxSubArray(self, nums):
10	"""
11	:type nums: List[int]
12	:rtype: int
13	"""
14	if not nums:
15	return 0
16	length = len(nums)
17	current = nums[0]
18	m = current
19	for i in range(1, length):
20	if current < 0:
21	current = 0
22	current += nums[i]
23	m = max(current, m)
24	return m

How to use 'maximum sum subarray of size k' in Python

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