10 examples of 'python date difference in days' in Python

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def days_ago(days):
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    """
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    Returns datetime object
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    """
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    return datetime.date.today() - datetime.timedelta(days=days)

517
def daysbetween(day1, month1, year1, day2, month2, year2):
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    """Given two dates it returns the number of days between them.
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    If date1 is earlier than date2 then the result will be positive."""
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    return daycount(year2, month2, day2) - daycount(year1, month1, day1)

41
def age_in_days(date):
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	return (datetime.now() - date).days

157
def _days_since(data_str: str) -> int:
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    """
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    Return number of days since the datetime passed as input in the form '%Y-%m-%d %H:%M:%S'.
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    This can be used to calculate how many days an update is in current state by passing
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    directly the 'date_pushed' or 'date_submitted' from the Update object.
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    This is also useful to easily mock the output, since datetime.datetime.utcnow()
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    cannot be mocked.
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    Args:
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        data_str: The 'date_pushed' or 'date_submitted' from the Update object.
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    Returns:
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        Number of days since the date in input.
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    """
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    update_time = datetime.datetime.strptime(data_str, '%Y-%m-%d %H:%M:%S')
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    return (datetime.datetime.utcnow() - update_time).days

29
def to_days_since_epoch(d):
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    return (d - datetime.datetime(1970, 1, 1)).days

9
def days_since_1900(date):
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    """Convert string date to days since 1/1/1900
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    Intakes a date month/day/year and returns number of days since 1/1/1900
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    convert_date('1/1/1950') -> 18262. Note 1900 was not leap year
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    """
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    days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]  
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    date_array = date.split('-')
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    month = int(date_array[1])
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    day = int(date_array[2])
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    year = int(date_array[0]) - 1900 #looking for number of days since 1900
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# Start with days in previous years
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    days_prev_years = year * 365
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# Add the appropriate leap years
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    leap_years = int(year/4)
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    if (year%4 == 0 and month < 3):
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        leap_years = leap_years - 1
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    days_prev_years += leap_years
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# Now count up the days this year, start with days in previous months
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    days_this_year = 0
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    for imonth in range(0,month-1):
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        days_this_year += days_in_month[imonth]
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# Add previous days this month
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    days_this_year += day-1
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    days = days_prev_years + days_this_year
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    return(days)

22
def age(bday, d=None):
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    """ http://www.djangosnippets.org/snippets/557/ """
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    if d is None:
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        d = datetime.date.today()
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    return (d.year - bday.year) - int((d.month, d.day) < (bday.month, bday.day))

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def first_day_of_month(date):
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    ddays = int(date.strftime("%d")) - 1
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    delta = timedelta(days=ddays)
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    return date - delta

244
def days_until(date):
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    """Calculate days until."""
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    show_date = dt_util.as_local(date)
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    now = dt_util.as_local(dt_util.now())
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    return int((show_date - now).total_seconds() / 86400)

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def _increment_day(date, i):
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    # increment date by i days
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    return date + datetime.timedelta(days=i)