10 examples of 'python get year from date' in Python

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@register.filter
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def year(date):
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    """
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    Gets the year (integer) from a date object.
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    Necessary to pipe through the to_date filter.
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    Example:
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    {{ some_timestamp|to_date|year }}
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    This doesn't work, unfortunately:
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    {{ some_timestamp|to_date.year }}
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    """
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    return date.year

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def get_ordinal_date(date):
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  # This is the only way I can get matplotlib to do the dates right.
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  return int(dates.date2num(get_date(date)))

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def toDate(mon, yr):
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    #Parse month
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    newMon = monthMapper(mon)
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    #Parse day
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    newDay = 1
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    #Parse year
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    if yr < 50:
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        yr += 2000
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    elif yr <= 99:
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        yr += 1900
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    newYr = yr
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    return date(newYr, int(newMon), newDay)

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def calc_easter_sunday(year):
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    a = year % 19
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    b = year // 100
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    c = year % 100
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    d = (19 * a + b - b // 4 - ((b - (b + 8) // 25 + 1) // 3) + 15) % 30
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    e = (32 + 2 * (b % 4) + 2 * (c // 4) - d - (c % 4)) % 7
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    f = d + e - 7 * ((a + 11 * d + 22 * e) // 451) + 114
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    month = f // 31
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    day = f % 31 + 1    
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    return datetime.date(year, month, day)

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@property
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def year(self):
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    return self.date.year

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def get_financial_year(year):
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    return get_financial_year_start(year), get_financial_year_start(year + 1) - timedelta(microseconds=1)

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def get_date_year(self):
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    return self.date.strftime("%Y")

9
def days_since_1900(date):
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    """Convert string date to days since 1/1/1900
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    Intakes a date month/day/year and returns number of days since 1/1/1900
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    convert_date('1/1/1950') -> 18262. Note 1900 was not leap year
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    """
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    days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]  
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    date_array = date.split('-')
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    month = int(date_array[1])
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    day = int(date_array[2])
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    year = int(date_array[0]) - 1900 #looking for number of days since 1900
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# Start with days in previous years
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    days_prev_years = year * 365
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# Add the appropriate leap years
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    leap_years = int(year/4)
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    if (year%4 == 0 and month < 3):
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        leap_years = leap_years - 1
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    days_prev_years += leap_years
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# Now count up the days this year, start with days in previous months
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    days_this_year = 0
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    for imonth in range(0,month-1):
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        days_this_year += days_in_month[imonth]
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# Add previous days this month
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    days_this_year += day-1
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    days = days_prev_years + days_this_year
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    return(days)

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def gen_date(date, year=None):
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    """
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    Generates date in APA format (currently outputs only year).
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    :param date:    input date, required
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    :type date:     str
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    :param year:    input year, default is None
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    :type year:     str or None
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    :return:        date annotation in APA format
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    :rtype:         str
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    """
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    year = parse_year(year) or parse_year(date)
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    if year:
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        return ' (%s).' % year
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    return ''

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def first_day_of_month(date):
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    ddays = int(date.strftime("%d")) - 1
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    delta = timedelta(days=ddays)
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    return date - delta