# 4 examples of 'python program to find maximum of three numbers using function' in Python

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``20def maximum3(a, b, c):21    """Computes maximum of given three numbers.22    23    	>>> maximum3(2, 3, 5)24        525    	>>> maximum3(12, 3, 5)26        1227    	>>> maximum3(2, 13, 5)28        1329    """``
``1def number_of_elements_equal_to_the_maximum():2    inputs = []3    number = None4    while number is None or number != 0:5        number = int(input())6        inputs.append(number)7    sorted_inputs = sorted(inputs, reverse=True)8    max_value = sorted_inputs9    count = 010    for element in sorted_inputs:11        if element == max_value:12            count += 113        else:14            break15    print(count)``
``1def find_integer(f):2    """Finds a (hopefully large) integer n such that f(n) is True and f(n + 1)3    is False. Runs in O(log(n)).45    f(0) is assumed to be True and will not be checked. May not terminate unless6    f(n) is False for all sufficiently large n.7    """8    # We first do a linear scan over the small numbers and only start to do9    # anything intelligent if f(4) is true. This is because it's very hard to10    # win big when the result is small. If the result is 0 and we try 2 first11    # then we've done twice as much work as we needed to!12    for i in range(1, 5):13        if not f(i):14            return i - 11516    # We now know that f(4) is true. We want to find some number for which17    # f(n) is *not* true.18    # lo is the largest number for which we know that f(lo) is true.19    lo = 42021    # Exponential probe upwards until we find some value hi such that f(hi)22    # is not true. Subsequently we maintain the invariant that hi is the23    # smallest number for which we know that f(hi) is not true.24    hi = 525    while f(hi):26        lo = hi27        hi *= 22829    # Now binary search until lo + 1 = hi. At that point we have f(lo) and not30    # f(lo + 1), as desired..31    while lo + 1 < hi:32        mid = (lo + hi) // 233        if f(mid):34            lo = mid35        else:36            hi = mid37    return lo``
``4def find_max_subarray(numbers):5    max_till_here = *len(numbers)6    max_value = 07    for i in range(len(numbers)):8        max_till_here[i] = max(numbers[i], max_till_here[i-1] + numbers[i])9        max_value = max(max_value, max_till_here[i])10    return max_value``