9 examples of 'python replace character in string' in Python

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329def replace_string(self, string, search_for, replace_with, count=-1):
330 """Replaces ``search_for`` in the given ``string`` with ``replace_with``.
331
332 ``search_for`` is used as a literal string. See `Replace String
333 Using Regexp` if more powerful pattern matching is needed.
334 If you need to just remove a string see `Remove String`.
335
336 If the optional argument ``count`` is given, only that many
337 occurrences from left are replaced. Negative ``count`` means
338 that all occurrences are replaced (default behaviour) and zero
339 means that nothing is done.
340
341 A modified version of the string is returned and the original
342 string is not altered.
343
344 Examples:
345 | ${str} = | Replace String | Hello, world! | world | tellus |
346 | Should Be Equal | ${str} | Hello, tellus! | | |
347 | ${str} = | Replace String | Hello, world! | l | ${EMPTY} | count=1 |
348 | Should Be Equal | ${str} | Helo, world! | | |
349 """
350 count = self._convert_to_integer(count, 'count')
351 return string.replace(search_for, replace_with, count)
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194def replace(string, old, new):
195 return string.replace(old, new)
34def replace_escape_char(a_string):
35
36 return _replace_by_regex(a_string, r'\[\s|\n]*')
52def replace(match):
53 s = match.group(0)
54 try:
55 return ESCAPE_DCT[s]
56 except KeyError:
57 n = ord(s)
58 if n < 0x10000:
59 return '\\u{0:04x}'.format(n)
60 #return '\\u%04x' % (n,)
61 else:
62 # surrogate pair
63 n -= 0x10000
64 s1 = 0xd800 | ((n >> 10) & 0x3ff)
65 s2 = 0xdc00 | (n & 0x3ff)
66 return '\\u{0:04x}\\u{1:04x}'.format(s1, s2)
220def string_replace(state):
221 '''
222 In third string on stack, replaces all occurences of second string with first string
223 '''
224 if len(state.stacks['_string']) > 2:
225 replace_this = state.stacks['_string'].stack_ref(1)
226 with_this = state.stacks['_string'].stack_ref(0)
227 in_this = state.stacks['_string'].stack_ref(2)
228 new_string = in_this.replace(replace_this, with_this)
229 state.stacks['_string'].pop_item()
230 state.stacks['_string'].pop_item()
231 state.stacks['_string'].pop_item()
232 state.stacks['_string'].push_item(new_string)
233 return state
105def replace_string(self, string, ignore_errors=False):
106 """Replaces variables from a string. Result is always a string."""
107 if not is_string(string):
108 return unic(string)
109 if self._cannot_have_variables(string):
110 return unescape(string)
111 return self._replace_string(string, ignore_errors=ignore_errors)
84def func_replace(context, text, old, new):
85 return text.replace(old, new)
470def replace(instring, indict):
471 """
472 This function provides a simple but effective template system for your html
473 pages. Effectively it is a convenient way of doing multiple replaces in a
474 single string.
475
476 Takes a string and a dictionary of replacements.
477
478 This function goes through the string and replaces every occurrence of every
479 dicitionary key with it's value.
480
481 ``indict`` can also be a list of tuples instead of a dictionary (or anything
482 accepted by the dict function).
483 """
484 indict = dict(indict)
485 if len(indict) > 40:
486 regex = re.compile("(%s)" % "|".join(map(re.escape, indict.keys())))
487 # For each match, look-up corresponding value in dictionary
488 return regex.sub(lambda mo: indict[mo.string[mo.start():mo.end()]],
489 instring)
490 for key in indict:
491 instring = instring.replace(key, indict[key])
492 return instring
15def replace(self, input):
16 # We use regex substitution here, since earlier implementation didn't
17 # work correctly if there are overlapping strings, i.e. doing
18 # ' foo foo '.replace(' foo ', ' bar ') gives just ' bar foo '
19 for source, _source_text, target in self.translations:
20 input = source.sub(target, input)
21 return input

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