5 examples of 'python string replace inplace' in Python

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def replace(string, old, new):
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    return string.replace(old, new)

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def replace(data, replacements):
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    """
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    Performs several string substitutions on the initial ``data`` string using
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    a list of 2-tuples (old, new) defining substitutions and returns the resulting
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    string.
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    """
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    return reduce(lambda a, kv: a.replace(*kv), replacements, data)

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def time_replace(self, inplace):
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    self.ts.replace(np.nan, 0.0, inplace=inplace)

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def replace_string(self, string, search_for, replace_with, count=-1):
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    """Replaces ``search_for`` in the given ``string`` with ``replace_with``.
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    ``search_for`` is used as a literal string. See `Replace String
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    Using Regexp` if more powerful pattern matching is needed.
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    If you need to just remove a string see `Remove String`.
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    If the optional argument ``count`` is given, only that many
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    occurrences from left are replaced. Negative ``count`` means
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    that all occurrences are replaced (default behaviour) and zero
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    means that nothing is done.
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    A modified version of the string is returned and the original
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    string is not altered.
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    Examples:
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    | ${str} =        | Replace String | Hello, world!  | world | tellus   |
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    | Should Be Equal | ${str}         | Hello, tellus! |       |          |
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    | ${str} =        | Replace String | Hello, world!  | l     | ${EMPTY} | count=1 |
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    | Should Be Equal | ${str}         | Helo, world!   |       |          |
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    """
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    count = self._convert_to_integer(count, 'count')
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    return string.replace(search_for, replace_with, count)

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def string_replace(state):
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	'''
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	In third string on stack, replaces all occurences of second string with first string
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	'''
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	if len(state.stacks['_string']) > 2:
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		replace_this = state.stacks['_string'].stack_ref(1)
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		with_this = state.stacks['_string'].stack_ref(0)
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		in_this = state.stacks['_string'].stack_ref(2)
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		new_string = in_this.replace(replace_this, with_this)
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		state.stacks['_string'].pop_item()
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		state.stacks['_string'].pop_item()
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		state.stacks['_string'].pop_item()
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		state.stacks['_string'].push_item(new_string)
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	return state